If cosec A = 2/√3, then find the value of A in terms of π ?

1 Answer
Ratnaker Mehta
Mar 9, 2018

# A=npi+(-1)^n(pi/3), n in ZZ#.

Explanation:

We know that, #sintheta=sinalpha rArr theta=npi+(-1)^nalpha, n in ZZ#.

Given that, #"cosecA="2/sqrt3#, we have, #sinA=sqrt3/2=sin(pi/3)#.

Hence, #A=npi+(-1)^n(pi/3), n in ZZ#.

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