If #costheta=-4/7#, what are the values of #sin theta# and #tan theta#?

1 Answer
Mar 5, 2017

#sin t = +- sqrt33/7#
#tan t = +- sqrt33/4#

Explanation:

Use trig identity:
#sin^2 t = 1 - cos^2 t#
In this case:
#sin^2 t = 1 - 16/49 = 33/49 # --> #sin t = +- sqrt33/7#
t could be either in Quadrant II and Quadrant III (cos t negative), there for both values could be answers.
The same for tan t where both answers are acceptable.
#tan t = sin/(cos) = +-(sqrt33)/7(- 7/4) = +- (sqrt33)/4#