If #dy/dx=2#, why is #dx/dy=1/2#?

Question

What is the math explanation of this concept?

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Answer 1 · 2017-05-10T05:10:19

#y = 2x + C. " If " C = 0: " " x = y/2, " So "dx/dy = 1/2#

#int dy/dx = int 2 dx#

#y = 2x + C#

If #C = 0: " " x = y/2#

So #dx/dy = 1/2(1) = 1/2#