# If f(x)= 1 for [-7,-3), 3 for [-3,1), and 5 for [1,5), how do you find f(1)?

Oct 1, 2016

$f \left(1\right) = 5$

#### Explanation:

If a function is given in such form with different formulas (here values) for different intervals of $x$ first step is to assign the argument to one of the intervals:

We have to calculate $f \left(1\right)$ so first we look where is $1$:

$1$ is a positive number, so it is NOT in [-7;-3)

The second interval's end point is $1$, but the interval is open there (indicated by the round bracket), so $1$ does NOT belong to this interval.

The third interval has a start point in $1$, and it is closed there (indicated by square bracket), so 1 in [1;5), so we use the third value as $f \left(1\right)$.

Answer: $f \left(1\right) = 5$