If f(x)= 1 for [-7,-3), 3 for [-3,1), and 5 for [1,5), how do you find f(1)?

1 Answer
Oct 1, 2016

#f(1)=5#

Explanation:

If a function is given in such form with different formulas (here values) for different intervals of #x# first step is to assign the argument to one of the intervals:

We have to calculate #f(1)# so first we look where is #1#:

#1# is a positive number, so it is NOT in #[-7;-3)#

The second interval's end point is #1#, but the interval is open there (indicated by the round bracket), so #1# does NOT belong to this interval.

The third interval has a start point in #1#, and it is closed there (indicated by square bracket), so #1 in [1;5)#, so we use the third value as #f(1)#.

Answer: #f(1)=5#