If #f(x)= 2 -x^(1/2)# and #g(x)= x^2- 9#, what is the domain of #g(x)div f(x)#?

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Answer 1 · 2017-09-23T08:57:12

#f(x) = (2 - x^(1/2))# and #g(x) = x^2 - 9#

so, #g(x) -: f(x) = (x^2 - 9)/(2 - x^(1/2))#

Now, the denominator cannot be zero

i.e. #2 - x^(1/2)!= 0#

so, #x^(1/2)!= 2#

Hence, #x!= 4#

Therefore, the domain is all values except #x = 4#

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