If $f (x) = 2 x^{2}$ $f(x)=2x^2$ , how do you find $f (x - 6)$ $f(x-6)$ ?

Question

3039 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-06T08:05:14

$f (x - 6) = 2 {(x - 6)}^{2} = 2 (x^{2} - 12 x + 36) = 2 x^{2} - 24 + 72$ $f(x-6)=2(x-6)^2=2(x^2-12x+36)=2x^2-24+72$

If $f (x) = 2 x^{2}$ $f(x)=2x^2$ , we can find $f (x - 6)$ $f(x-6)$ by substituting in $x - 6$ $x-6$ for everywhere that has an $x$ $x$ :

$f (x - 6) = 2 {(x - 6)}^{2} = 2 (x^{2} - 12 x + 36) = 2 x^{2} - 24 + 72$ $f(x-6)=2(x-6)^2=2(x^2-12x+36)=2x^2-24+72$

If f(x)=2x2f(x)=2x^2, how do you find f(x−6)f(x-6)?