Question

If `f(x) = (3x-1)/2` and `f^-1` is the inverse of `f`, what is the value of `f^-1(3)`?

Answer 1

`7/3`

Explanation:

`f^-1(y) = x = (3y - 1)/2 => 2x = 3y - 1 => y = (2x + 1)/3`

`f^-1(3) = (2*3 + 1)/3`