Question

If f(x)=3x if x<0, x+1 if 0≤ x≤ 2, and (x-2)^2 if x>2, how do you find f(0)?

Answer 1

`f(0)=1`.

Explanation:

To find `f(0)`, we have to examine, where in the defn. of `f`, we are permitted to take the value of `x=0`.

We find that, this happens here : `f(x)=x+1, if 0<=x<=2`

Therefore, `f(0)=0+1=1`.