If #f(x)=5x#, #g(x)=1/x#, and #h(x)=x^3#, how do you find #(5h(1)-2g(3))/(3f(2))#?
Now let's plug in the values for those functions:
Now we can simplify
And we can multiply the numbers in the denominator
Now let's try and get rid of that ugly fraction in a fraction! We can do that by multiplying the entire fraction by
Multiplying through on both sides:
Now simplify the multiplications:
Now subtract in the numerator... and...
There you have it!