If #f(x) = sqrt(2x+3)/(6x-5)#, what is #f(1/2)#?
1 Answer
Jul 7, 2018
Explanation:
#"substitute "x=1/2" into "f(x)#
#f(color(red)(1/2))=(sqrt(2xxcolor(red)(1/2)+3))/(6xxcolor(red)(1/2)-5)#
#color(white)(xxxxx)=(sqrt(1+3))/(3-5)#
#color(white)(xxxxx)=sqrt4/(-2)=2/(-2)=-1#