If #f(x)=x^2+1#, how do you find f(x+2)?
1 Answer
Feb 13, 2016
# x^2 + 4x + 5
Explanation:
to evaluate f(x+2) ,substitute x = x + 2 in f(x)
hence
# f(x+2) = (x+2)^2 + 1 # now
# (x+2)^2 = x^2 + 4x +4 #
# rArr f(x+2) = x^2 + 4x + 4 + 1 = x^2 + 4x + 5 #
