# If f(x) = (x - 2)^2; g (x) = x +3 , then what is (f + 2g)(4)?

May 26, 2017

18

#### Explanation:

First, find the double of $g \left(x\right)$:

$2 g \left(x\right) = 2 \left(x + 3\right)$

Now add this to $f \left(x\right)$:

$f + 2 g = {\left(x - 2\right)}^{2} + 2 \left(x + 3\right)$

Now plug in $4$:

$\left(f + 2 g\right) \left(4\right) = \left[{\left(4 - 2\right)}^{2} + 2 \left(4 + 3\right)\right]$

This results in:

$\Rightarrow \left[4 + 14\right] = 18$