If #f(x) = (x - 2)^2#; #g (x) = x +3 #, then what is (f + 2g)(4)?

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Answer 1 · 2017-05-26T15:12:16

18

First, find the double of #g(x)#:

#2g(x)=2(x+3)#

Now add this to #f(x)#:

#f+2g=(x-2)^2+2(x+3)#

Now plug in #4#:

#( f + 2g ) ( 4 ) = [(4-2)^2+2(4+3)]#

This results in:

#rArr [4+14] = 18#