Question

If `f(x)=x^2+3x-1` and `g(x)=x^3+4x^2+1`, what is `(f-g)(x)`?

Answer 1

`(f-g)(x)=-x^3-3x^2+3x-2`

Explanation:

Given -

`f(x)=x^2+3x-1`
`g(x)=x^3+4x^2+1`

`(f-g)(x)=f(x)-g(x)`
`(f-g)(x)=(x^2+3x-1)-(x^3+4x^2+1)`

`(f-g)(x)=x^2+3x-1-x^3-4x^2-1`
`(f-g)(x)=-x^3-3x^2+3x-2`