If #f(x) = x^2 - x# and #g(x) = 3x + 1# how do you find #g(f(sqrt2))#?
1 Answer
May 20, 2017
Explanation:
#f(color(red)(sqrt2))=(color(red)(sqrt2))^2-color(red)(sqrt2)=2-sqrt2#
#"to evaluate " g(f(sqrt2)))#
#"substitute " f(sqrt2)" into " g(x)#
#rArrg(f(sqrt2)))=3(2-sqrt2)+1#
#color(white)(rArrg(f(sqrt2x)))=6-3sqrt2+1#
#color(white)(rArrg(f(sqrt2x)))=7-3sqrt2#
