If $f (x) = x^{2} - x$ $f(x)=x^2-x$ , how do you find $f (x) + 5$ $f(x)+5$ ?

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Answer 1 · 2016-09-10T14:24:32

$x^{2} - x + 5$ $x^2-x+5$

To find f(x) + 5 , just add 5 to the value of f(x).

$\Rightarrow f (x) + 5 = x^{2} - x + 5 = x^{2} - x + 5$ $rArrf(x)+5=color(red)(x^2-x)+5=x^2-x+5$

If f(x)=x^2-xf(x)=x2−xf(x)=x^2-x, how do you find f(x)+5f(x)+5f(x)+5?