If #f(x) = x(2x-1)#, what is #f(0)#?

1 Answer
Jan 21, 2018

See a solution process below:

Explanation:

To find #f(0)# substitute #color(red)(0)# for every occurrence of #color(red)(x)# in #f(x)#:

#f(color(red)(x)) = color(red)(x)(2color(red)(x) - 1)# becomes:

#f(color(red)(0)) = color(red)(0)((2 xx color(red)(0)) - 1)#

#f(color(red)(0)) = color(red)(0)(0 - 1)#

#f(color(red)(0)) = color(red)(0) xx -1#

#f(color(red)(0)) = 0#