If f(x)=x^3-3-2xf(x)=x3−3−2x, and g(x)=x-1g(x)=x−1, what is (f*g)(x)(f⋅g)(x)?
2 Answers
Jun 18, 2018
Explanation:
Jun 18, 2018
Explanation:
(f*g)(x)=f(x)xxg(x)(f⋅g)(x)=f(x)×g(x)
=(x^3-3-2x)(x-1)=(x3−3−2x)(x−1)
=color(red)(x^3)(x-1)color(red)(-3)(x-1)color(red)(-2x)(x-1)=x3(x−1)−3(x−1)−2x(x−1)
=x^4-x^3color(blue)(-3x)+3-2x^2color(blue)(+2x)=x4−x3−3x+3−2x2+2x
=x^4-x^3-2x^2-x+3=x4−x3−2x2−x+3