If #g(a) = -4a-4# and #h(a) = 2a+3#, what is #(g*h)(0)#?

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Answer 1 · 2018-03-19T02:14:31

# (g*h)(0) = -16 #

We have:

# g(a) = -4a-4#
#h(a) = 2a+3#

And so:

# (g*h)(0) = g(h(0)) #

Now:

# h(0) = 0 + 3 = 3#

Thus:

# (g*h)(0) = g(3) #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ = -4*3-4 #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ = -12-4 #
# \ \ \ \ \ \ \ \ \ \ \ \ \ \ = -16 #