If #g(x) = (1/3)^x#, what is #g(2)#?

2 Answers
Mar 23, 2017

#1/9#

Explanation:

To evaluate g( 2 ) substitute x = 2 into g( x )

#g(color(red)(2))=(1/3)^(color(red)(2))#

#=1/3xx1/3#

#=(1xx1)/(3xx3)#

#=1/9#

#g(2)=(1/3)^2=1/9#

Explanation:

When we have a function, such as #g(x)="something"#, and are given a value to substitute in (like with #g(2)#), we're asked to take all instances of #x# and replace in the value 2).

And so we take

#g(x)=(1/3)^x#

and write:

#g(2)=(1/3)^2#

We can now simplify:

#(1/3)^2=1^2/3^2=1/9#