Question

If `g(x) = (1/3)^x`, what is `g(2)`?

Answer 1

`1/9`

Explanation:

To evaluate g( 2 ) substitute x = 2 into g( x )

`g(color(red)(2))=(1/3)^(color(red)(2))`

`=1/3xx1/3`

`=(1xx1)/(3xx3)`

`=1/9`

Answer 2

`g(2)=(1/3)^2=1/9`

Explanation:

When we have a function, such as `g(x)="something"`, and are given a value to substitute in (like with `g(2)`), we're asked to take all instances of `x` and replace in the value 2).

And so we take

`g(x)=(1/3)^x`

and write:

`g(2)=(1/3)^2`

We can now simplify:

`(1/3)^2=1^2/3^2=1/9`