Question

If `g(x)=1^(-x) - x+4`, what is `g(-1)`?

Answer 1

See the entire solution process below:

Explanation:

To find `g(-1)` we need to substitute `color(red)(-1)` for every occurrence of `color(red)(x)` in `g(x)` and then calculate the result:

`g(color(red)(x)) = 1^-color(red)(x) - color(red)(x) + 4` becomes:

`g(color(red)(-1)) = 1^-color(red)(-1) - color(red)((-1)) + 4`

`g(color(red)(-1)) = 1^color(red)(1) + color(red)(1) + 4`

`g(color(red)(-1)) = 1 + color(red)(1) + 4`

`g(color(red)(-1)) = 6`