If #g (x) = 3^2 - x + 17#, then how do you find g (2)?

Question

1763 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-07T22:46:13

In case there is an error in the question, lets look at #g(x) = x^2-x+17#

For #g(x) = x^2-x+17#

It may be helpful to think of it this way:

#g(color(red)(x)) = (color(red)(x))^2-(color(red)(x))+17#

To find #g(2)#, we will replace all of the #color(red)(x)#'s with #color(red)(2)#s.

#g(color(red)(2)) = (color(red)(2))^2-(color(red)(2))+17#

We get:

#g(2) = (2)^2 - (2) + 17#

# = 4-2+17#
# = 2+17#
# = 19#

That is: #g(2) = 19#

Note: I am convinced that the use of parentheses in the first step is a very good habit to develop.