If #g(x) = 5 - sqrt(x+30)#, how do you solve g(6)?

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Answer 1 · 2015-10-16T23:31:08

#g(6) = -1#

Your function is defined as

#g(x) = 5 - sqrt(x + 30)#

In order to find the value of #g(6)#, you need to evaluate the function at #x = 6#.

Simply put, what will be the value of #g# when #x = 6#? Replace #x# with #6# in the expression of the function to get

#g(6) = 5 - sqrt((6) + 30)#

#g(6) = 5 - sqrt(36) = 5 - 6 = -1#

The value of #g# at #x=6# will thus be

#g(6) = -1#