# If g(x)= { 7 if x≤0 , 1/x if x >0, how do you find g(1)?

$g \left(1\right) = 1$
$g \left(1\right) = g \left(x\right)$ with $x = 1$
and according to the definition of $g \left(x\right)$
$g \left(x\right) = \frac{1}{x}$ when $x > 0$
and since $1 > 0$
$g \left(1\right) = \frac{1}{1} = 1$