If g ( x ) = \root [ 3] { x ^ { 2} - 1} + 2\sqrt { x + 1} , what is g(3)?

2 Answers
Apr 11, 2018

g(3) =6

Explanation:

Just substitute 3 in wherever there's an x

g(3)=root(3)(3^2-1) + 2sqrt(3+1)
g(3) = root(3)8 + 2sqrt4
g(3) = 2 + 2sqrt4
g(3) = 2 + 2xx2
g(3) = 2 + 4
g(3) =6

Apr 11, 2018

g(3)=6

Explanation:

Plug 3 in for x

g(3)=root3(3^2-1)+2sqrt(3+1)

Simplify

g(3)=root3(9-1)+2sqrt(4)
g(3)=root3(8)+2sqrt(4)
g(3)=2+2(2)
g(3)=2+4
g(3)=6