If #g(x)=-x^2-2x-4# , what is #g(0)#?

Question

3596 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-20T10:15:54

#g(0)=-4#

#"to evaluate "g(0)" substitute x = 0 into "g(x)#

#rArrg(color(red)(0))=-color(red)(0)^2-(2xxcolor(red)(0))-4=-4#

Answer 2 · 2018-04-20T13:26:27

#-4#

Given: #g(x)=-x^2-2x-4#

For #g(0)#, plug in #x=0# into the function to get:

#g(0)=-0^2-2*0-4#

#=0-0-4#

#=0-4#

#=-4#