Question

If `g( x ) = x ^ { 2} - 3x - 7`, how would you find `(g*g)(-2)`?

Answer 1

`-7`

Explanation:

`(g.g)(-2) = g^2(-2) = g(g(-2))`

#g(-2) = (-2)^2 - 3(-2) -7 =4+6-7=3

since `g(-2) =3`, then,
`g(g(-2)) = g(3) = 3^3 - 3(3)-7=9-9-7 = -7`