# If [H_3O^+] = 8.26 times 10^-5 M, what is the pH of the solution?

$p H = 4.08 \ldots \ldots \ldots \ldots$
$p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$
=-log_10(8.26xx10^-5)=??