If #h(t) = 10t^2-2t+7#, what is #h(3)#?

1 Answer
smendyka
Jul 28, 2017

See a solution process below:

Explanation:

To find #h(3)# substitute #color(red)(3)# for each occurrence of #color(red)(t)# in the function #h(t)# and calculate the result:

#h(color(red)(t)) = 10color(red)(t)^2 - 2color(red)(t) + 7# becomes:

#h(color(red)(3)) = (10 * color(red)(3)^2) - (2 * color(red)(3)) + 7#

#h(color(red)(3)) = (10 * color(red)(9)) - 6 + 7#

#h(color(red)(3)) = 90 + 1#

#h(color(red)(3)) = 91#

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