# If h(x) = -x^2 - 3x, how do you solve h(-4)?

Apr 14, 2018

h(-4) = -4

#### Explanation:

Since x is given (x = -4). Then, all you need to do is log in -4 for each value of x
h(-4) = $- {\left(- 4\right)}^{2}$ -3(-4)
h(-4) = -(16) + 12 = -4

Apr 14, 2018

$h \left(- 4\right) = - 4$

#### Explanation:

$h \left(x\right) = - {x}^{2} - 3 x$

$h \left(- 4\right) = - {\left(- 4\right)}^{2} - 3 \left(- 4\right)$

h(-4)=-16-(-12))

$h \left(- 4\right) = - 16 + 12$

$h \left(- 4\right) = - 4$