If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?

1 Answer
Feb 7, 2016

Answer:

Approx. #0.10# #mol*L^-1#

Explanation:

#"Concentration"# #=# #("MOLES of SOLUTE")/("Volume of SOLUTION")#

So all we need to is to calculate the one quantity; #"Volume of SOLUTION"# has been specified to be #150# #mL#.

So, #"MOLES of SOLUTE"# #=# #0.15*mol*L^-1# #xx# #100xx10^-3L# #=# #??"mol"#; this was our starting solution.

And final #"CONCENTRATION"# #=#

#(0.15*mol*cancel(L^-1)xx100xx10^-3cancel(L))/(150xx10^-3*L)# #=# #??mol*L^-1#