Question

If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?

Answer 1

Approx. `0.10` `mol*L^-1`

Explanation:

`"Concentration"` `=` `("MOLES of SOLUTE")/("Volume of SOLUTION")`

So all we need to is to calculate the one quantity; `"Volume of SOLUTION"` has been specified to be `150` `mL`.

So, `"MOLES of SOLUTE"` `=` `0.15*mol*L^-1` `xx` `100xx10^-3L` `=` `??"mol"`; this was our starting solution.

And final `"CONCENTRATION"` `=`

`(0.15*mol*cancel(L^-1)xx100xx10^-3cancel(L))/(150xx10^-3*L)` `=` `??mol*L^-1`