# If I have 4.00 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

Nov 3, 2016

$T = \frac{P V}{n R}$ $\cong$ $200 \cdot K$

#### Explanation:

We use the Ideal Gas equation, $P V = n R T$, and solve for $T$, which here has units of $\text{degrees Kelvin}$.

$T = \frac{5.6 \cdot \cancel{a t m} \times 12 \cdot \cancel{L}}{0.0821 \cdot \cancel{L} \cdot \cancel{a t m} \cdot {K}^{-} 1 \cdot \cancel{m o {l}^{-} 1} \times 4.00 \cdot \cancel{m o l}}$

We are left with units of $\frac{1}{{K}^{-} 1} = K$, units of temperature as required.