If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature of 200. K, and then I raise the pressure to 14.0 atm and increase the temperature to 300. K, what is the new volume of the gas?

Oct 11, 2016

The two actions work against each other.

Explanation:

Raising the temperature will increase the volume:
${V}_{T} = \frac{300 K}{200 K} \times 24.0 L = 36.0 L$

Increasing the pressure will decrease the volume:
${V}_{T , p} = \frac{10.0 a t m}{14.0 a t m} \times 36.0 L \approx 25.7 L$

It doesn't matter if you first do the one and then the other, or the other way around, or both simultaneously