If log base 10 (2) = 0.301 & log base 10 (3) = 0.477, what does log base 10 (15) =?

1 Answer
Jan 28, 2016

Answer:

I found: #1.176#

Explanation:

We can write it as:
#log_(10)(15)=log_(10)(30/2)#
using the property of logs of a fraction we get:
#log_(10)(30/2)=log_(10)(30)-log_(10)(2)=#
and:
#=log_(10)(10*3)-log_(10)(2)=#
we use the property of the log of a product to get:
#log_(10)(10)+log_(10)(3)-log_(10)(2)=#
#=1+0.477-0.301=1.176#