If log4 = 0.602, evaluate log2.5?

Question

Bases are 10.

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Answer 1 · 2017-09-13T14:14:04

The answer is #=0.398#

We need

#log(a/b)=loga-logb#

#log_10 2.5=log_10 (10/4) =log_10 10 -log_10 4#

#log_10 4=0.602#

#log_10 10=1#

Therefore,

#log_10 2.5=log_10 (10/4) =1-0.602=0.398#