# If molarity moles/liter, then how many grams of NaCl are needed to make 3.550 liter of a 1.30 M solution?

##### 1 Answer

#### Explanation:

**Molarity** is indeed defined as moles of solute per liter of solution, but it can also be expressed as *grams of solute* per liter of solution.

As you know, a **mole** of solute in

In your case, a **moles** of sodium chloride, the solute, for every

You can use the **molar mass** of sodium chloride to convert this to *grams* of sodium chloride for every

#1.30 color(red)(cancel(color(black)("moles NaCl"))) * "58.44 g"/(1color(red)(cancel(color(black)("mole NaCl")))) = "75.97 g"#

You can now say that a

#3.550 color(red)(cancel(color(black)("L solution"))) * "75.97 g NaCl"/(1color(red)(cancel(color(black)("L solution")))) = color(darkgreen)(ul(color(black)("270. g NaCl")))#

The answer is rounded to three **sig figs**.