If #s(x)=x-7# and #f(x)=4x^2-x+3#, what is #(t*s)(x)#?

1 Answer
planetarymemes
Jan 15, 2018

#4x^2-57x+202#

Explanation:

Plug #s(x)# into #t(x)# where you would normally put an #x# value
#4(x-7)^2-(x-7)+3#
Distribute to get #4(x^2-14x+48)-x+7+3#
Continue distributing to get #4x^2-56x+192-x+7+3#
Combine like terms to get #4x^2-57x+202#

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