If #s(x)= x -7 and t(x) = 4x^2 - x +3#, how do you solve # (t*s)(x)#?

1 Answer
salamat
Jun 19, 2017

#(t*s)(x) = 4x^2 - 57x + 206#

Explanation:

#s(x) = x -7#, #t(x) = 4x^2 - x + 3#

replace #s(x)# in #t(x)#
#(t*s)(x) = t(s(x)) = 4(x-7)^2 - (x - 7) + 3#

#(t*s)(x) = 4(x^2 - 14x + 49) - x + 7 + 3#

#(t*s)(x) = 4x^2 - 56x + 196 - x +10#

#(t*s)(x) = 4x^2 - 57x + 206#

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