If s(x)= x -7 and t(x) = 4x^2 - x +3, how do you solve (t*s)(x)?

1 Answer
Jun 19, 2017

(t*s)(x) = 4x^2 - 57x + 206

Explanation:

s(x) = x -7, t(x) = 4x^2 - x + 3

replace s(x) in t(x)
(t*s)(x) = t(s(x)) = 4(x-7)^2 - (x - 7) + 3

(t*s)(x) = 4(x^2 - 14x + 49) - x + 7 + 3

(t*s)(x) = 4x^2 - 56x + 196 - x +10

(t*s)(x) = 4x^2 - 57x + 206