If sec=-√10, what are the remaining five trigonometric functions?

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Answer 1 · 2018-04-02T11:33:51

#cos x = -1 / sqrt10, tan x = +- 3, cot x = +- 1/3, sin x = +-3/sqrt10, csc x = +- sqrt10 / 3#

#sec x = -sqrt10#

#cos x = 1 / sec x = -1/sqrt10#

#1 + tan^2 x = sec^2 x#

#tan x = sqrt(sec^2x - 1) = sqrt9 = +-3#

#cot x = 1/ tan x = +- 1/3#

#sin x = tan x * cos x = +- 3 / sqrt10#

#csc x = 1 / sin x = +- sqrt10 / 3#