If #sinA + cosecA + 2 = 0# then, #sin^(2017)(A) + cosec^(2016)(A) + 1# is equal to?
A) 1
B) 0
C) 2
D) 3
A) 1
B) 0
C) 2
D) 3
1 Answer
Sep 13, 2017
So
A) 1
B) 0
C) 2
D) 3
So