Question

If someone inhales 2.10 L of gas at a temperature of 18.5 degrees C, and it warms to a temperature of 38 degrees C in his lungs, what is the new volume of the gas?

Answer 1

`color(red)(2.24L)`

Explanation:

Charle's Law `(V1)/(T1)=(V2)/(T2)`
`T` -temperature's unit must be in Kelvin `K=C^@+273.15`

So, you only need to convert your temperature to Kelvin
`18.5^@C+273.15=291.65`
`38^@C+273.15=311.15`

`V_1=color(red)(2.10L)`
`T_1=color(red)(291.65K)`
`V_2=color(red)(?)`
`T_2=color(red)(311.15K)`

Now, rearrange the formula to get `V_2`
`V_2=V_1*(T_2)/(T_1)`
`V_2=color(red)(2.10L)*color(red)(311.15cancel(K))/(color(red)(291.65cancel(K))`
`V_2=color(red)(?)`