If the #A=36pi*m^2, what is the radius of a circle?

Question

545 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-16T02:46:06

#r= 6m#

#A=pir^2#

To solve for #r#:
#r= sqrt(A/(pi)#

#r = +-sqrt((36pim^2)/pi)#

#r = +-sqrt((36cancel(pi)m^2)/cancelpi)#

#r= +-sqrt(36m^2)#

#r= +-6 m#

Since distance can't be negative
#r= 6m#