# If the earth is a grain of sand what is the universe equivalent to?

Jul 7, 2016

The observable universe would be smaller than the volume of the Milky Way but far larger than the largest known star.

#### Explanation:

$0.0025 f l o z = 7.29 \cdot {10}^{- 8} {m}^{3}$

Now, let's get the Earth's volume:

$2.598 \cdot {10}^{11} m {i}^{3} = 1.083 \cdot {10}^{21} {m}^{3}$

We need the volume of the observable universe:

Set up proportions:

$\frac{1.083 \cdot {10}^{21} {m}^{3}}{7.29 \cdot {10}^{- 8} {m}^{3}} = \frac{3.387 \cdot {10}^{80} {m}^{3}}{x}$

$x = 2.279 \cdot {10}^{52} {m}^{3}$

This is about 26,916 cubic light years.