If the equation given is #y=2x^2# and the point given is (-1,2), how would you find the p value from the form #(x-0)^2=4p(y-k)#?
1 Answer
Aug 8, 2018
Explanation:
We can rearrange the formula:
Therefore, we know that the coefficient of
We could also have just done this with the given point by plugging in the known values of
Since we can see that the vertical shift is 0 (since the function also intercepts 0), we get