If the equation k(10x-5)=2(3+x)-7 has infinitely many solutions and k is a constant, what is the value of k?

2 Answers
May 13, 2018

k=1/5

Explanation:

Given: k(10x-5)=2(3+x)-7

For an infinite count of solutions then their graphs are parallel and coincidental over the whole domain/range.

Divide both sides by (10x-5)

k=(2x-1)/(10x-5)

k=(2x-1)/(5(2x-1))

k= 1/5

May 13, 2018

k=1/5

Explanation:

k(10x-5)=2(3+x)-7
k(10x-5)=6+2x-7
k(10x-5)=2x-1
k=(2x-1)/(10x-5)
k=(1*cancel(2x-1))/(5*cancel(2x-1))
k=1/5
\0/ here's our answer!