# If the equilibrium constant (K) = 100, this reaction favors the (reactants/products) and proceeds (very little/almost to completion). Equilibrium?

##### 1 Answer
May 26, 2017

Let's take the general equilibrium reaction:
$w A + x B \leftrightarrow y C + z D$

In which A, B, C and D are compounds and w,x,y,z are coefficients.
To determine the equilibrium constant, we write:

K=([C]^yxx[D]^z)/([A]^wxx[B]^x)color(white)(aaaa)color(white)(color(blue)(1.)/color(blue)(2.)

The equilibrium constant says something about the proceeding of the reaction: does it favour the forward reaction or the backwards reaction? The blue numbers represent the concentration of the two sides:

1. "Combined concentration products"
2. "Combined concentration reactants"

We have given that $K = 100$, this means that side 1 must be a larger number than number 2. Only then will K be larger than 1. This means that the combined concentration of side 1 (products) is larger than the combined concentration of side 2.
Therefore the reaction is favoured to the right side (the product side). Since K=100 is pretty big, the reaction will probably go almost into completion.

By following this method, you can figure out that

K>>1 $\textcolor{w h i t e}{a a}$ $\textcolor{b l u e}{|}$Product favored $\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Close to completion
K>1 $\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Product favored$\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$ Very little
K=1 $\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Equilibrium$\textcolor{w h i t e}{a a a a a a a}$ $\textcolor{b l u e}{|}$-
K<1 $\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Reactant favored$\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Very little
K<<1 $\textcolor{w h i t e}{a a}$ $\textcolor{b l u e}{|}$Reactant favored$\textcolor{w h i t e}{a a a}$ $\textcolor{b l u e}{|}$Close to completion