"let elapsed time to peak point for faster stone be " t_1
3v:"velocity of faster stone"
t_1=(3v)/g
"let elapsed time to peak point for slower stone be " t_2
v:"velocity of slower stone"
t_2=(v)/g
"Let's find the ratio " t_1 / t_2
t_1/t_2=(3cancel(v))/cancel(g)* cancel( g)/cancel(v)
t_1/t_2=3
"Since the movement is symmetric, the time to reach "
"the maximum point is equal to half of the duration of the flight."
t_1=10/2=5 sec.
5/t_2=3
t_2=5/3 sec.
"flight time for slower stone "=2*5/3=10/3 sec.
H=v^2/(2g)" slower stone's maximum height"
x=(3v)^2/(2g)=(9v^2)/(2g)" faster stone's maximum height"
"let find the ratio " H/x
H/x=cancel(v^2)/(cancel(2g))*(cancel(2g))/(9cancel(v^2)
H/x=1/9
x=9H