If the length of one of the legs of a right triangle is 10 and the length of the other leg is 24, what is the length of the hypotenuse?

Nov 11, 2015

26.

Explanation:

This problem can be solved using Pythagoras's theorem:
${a}^{2} + {b}^{2} = {c}^{2}$, where $a$ and $b$ are the legs and $c$ is the hypotenuse. Therefore:
${10}^{2} + {24}^{2} = h i {p}^{2}$

Solve the squares:
$100 + 576 = h i {p}^{2}$

$676 = h i {p}^{2}$
$h i p = \sqrt{676} = 26$.