# If the letters of the word Mississippi are placed in a hat, what is the probability that the first two letters drawn are both "i" if the first letter drawn is not replaced?

Oct 22, 2015

$\frac{6}{55}$

#### Explanation:

There are $11$ (non-unique) letters in "Mississippi"
of which $4$ are $i$

A: picking a letter "i" from the letters: "iiiiMsssspp"
P(A) $= \frac{4}{11}$

B|A: picking a letter "i" from the letters: "iiiMsssspp"
P(B|A) $= \frac{3}{10}$

P(A&B) = P(A)*P(B|A) = 4/11*3/10 = 12/110 = 6/55