Question

If the man pushes with a force of 1005N, the box will slide up the ramp at a rate of 1.1m/s². How much normal force is acting on the box?

Answer 1

I may be wrong but I think that you need one additional information (the mass perhaps?).

Explanation:

Consider the diagram:

Where:
`F=1005N`

From Newton`s Second Law, `SigmavecF=mveca`, for `x` and `y` directions:
`{(F-w_x=ma_x),(N-w_y=0):}` where `a_x=1.1m/s^2`

with your data:
`1005-mgsin(alpha)=1.1m`
`N=mgcos(alpha)`

The problem here is that I have three unknowns, `m, alpha and N` and only 2 equations!