If the perimeter of a rectangle is 68 inches and the length is 10 inches more than its width, what is the area of the rectangle?

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Answer 1 · 2018-04-18T05:06:34

#264 i n^2#

Recall that the perimeter #p# of a rectangle is given by

#p=2l+2w, l, w# represent length and width (respectively).

We're told the following:

#p=68#

#l=w+10#

So, we may rewrite as follows:

#68=2(w+10)+2w#

#68=2w+20+2w#

Combine like terms:

#4w+20=68#

Solve for #w:#

#4w=48#

#w=12#

Now, we can get the length:

#l=w+10=12+20=22#

The area #A# of a rectangle is given by

#A=lw.# Knowing #w=12, l=22, A=12(22)=264i n^2#